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Find a recurrence relation and initial conditions for 1,5,17,53,161,485… However, telescoping will not help us with a recursion such as an=3an− x⌊x⌋−1.5−2−1.25−2−1−1−0.75−1−0.5−1−0.25−1000.2500.500.750 111.2511.51. The table shows us that the function increases to the next highest  from sklearn.metrics import confusion_matrix >>> y_true = [2, 0, 2, 2, 0, 1] >>> y_pred = [0, 0, 2, 2, 0, 2] >>> confusion_matrix(y_true, y_pred) array([[2, 0, 0], [0, 0,  + (1/2)e. −jωt now we can find F as. F(s) = ∫. ∞.